16(3-u)-u^2(3-4)=0

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Solution for 16(3-u)-u^2(3-4)=0 equation: 



16(3-u)-u^2(3-4)=0

We add all the numbers together, and all the variables

-u^2(-1)+16(-1u+3)=0

We multiply parentheses

-u^2(-1)-16u+48=0

We move all terms containing u to the left, all other terms to the right

-u^2(-1)-16u=-48

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